(x/5)^log_b(5) - (x/6)^log_b(6) = 0

  • zkfcfbzr@lemmy.worldOP
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    6 months ago

    Yes, though I prefer spoilered answers with work (especially since something like Wolfram|Alpha can just spit out the answer here)

    I’m curious about your retracted edit, since I saw your original message had just the correct answer - why 30k?

    • Lojcs@lemm.ee
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      6 months ago

      I thought 0 also works so maybe it’s multiples of 30 but then tried 60 and it didn’t work

      • zkfcfbzr@lemmy.worldOP
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        6 months ago
        spoilers

        0 does work as a trivial solution, since 0^a = 0^b always holds, but yea, 30’s the only other one - the key comes down to the fact that a^log(b) = b^log(a) in general, and 30 is what achieves that here