(x/5)^log_b(5) - (x/6)^log_b(6) = 0

  • Lojcs@lemm.ee
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    6 months ago

    I thought 0 also works so maybe it’s multiples of 30 but then tried 60 and it didn’t work

    • zkfcfbzr@lemmy.worldOP
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      6 months ago
      spoilers

      0 does work as a trivial solution, since 0^a = 0^b always holds, but yea, 30’s the only other one - the key comes down to the fact that a^log(b) = b^log(a) in general, and 30 is what achieves that here