(x/5)^log_b(5) - (x/6)^log_b(6) = 0
i got it, no calculator needed
spoiler
https://gmtex.siri.sh/fs/1/School/Extra/Maths/Challenges solutions/log-5and6.html
All good - this is pretty much what I did as well.
i showed the question to my friend who isnt particularly bright in maths, he said 30 by just looking at it, i freaked out a bit but it might just have been a lucky guess
Spoiler
30?
E: 30k?Yes, though I prefer spoilered answers with work (especially since something like Wolfram|Alpha can just spit out the answer here)
I’m curious about your retracted edit, since I saw your original message had just the correct answer - why 30k?
I thought 0 also works so maybe it’s multiples of 30 but then tried 60 and it didn’t work
spoilers
0 does work as a trivial solution, since 0^a = 0^b always holds, but yea, 30’s the only other one - the key comes down to the fact that a^log(b) = b^log(a) in general, and 30 is what achieves that here